In a series circuit with two identical resistors, how is the PD distributed across them?

In a series circuit with two identical resistors, how is the PD distributed across them?

• A. Inversely proportional to resistance
• B. Equally across each resistor
• C. All across the first resistor
• D. None across resistors

Answer: (B)

Voltage in a series circuit is split among components in proportion to their resistance, with the same current flowing through each. The drop across a resistor is V = I × R. Since the two resistors have the same resistance, their voltage drops are equal. The total supply voltage is the sum of these drops, so each resistor takes half of the total. For example, with a 12 V supply, each resistor would drop 6 V. The other ideas don’t fit because in series the voltage isn’t all across one element, nor is it zero or inversely related to resistance.

Voltage in a series circuit is split among components in proportion to their resistance, with the same current flowing through each. The drop across a resistor is V = I × R. Since the two resistors have the same resistance, their voltage drops are equal. The total supply voltage is the sum of these drops, so each resistor takes half of the total. For example, with a 12 V supply, each resistor would drop 6 V. The other ideas don’t fit because in series the voltage isn’t all across one element, nor is it zero or inversely related to resistance.